This tutorial will discuss about unique ways to remove every nth element from a numpy array.

Suppose we have a numpy array of numbers, like this,

numbers = np.array([34, 35, 78, 61, 56, 35, 90, 35])

We want to delete every 2nd element from this array.

For this we will create a boolean array or a mask, where every Nth element will be marked as False like this,

# Create a mask where each Nth element # is marked as False mask = np.arange(len(numbers)) % n != 0 mask = ~mask

It will return a boolean array where every Nth element is False. Then we can pass this modified boolean sequence into the subscript operator of number array like this,

# Remove every Nth element from the array numbers = numbers[mask]

It will return a copy of number array after removing every Nth element from the original array.

In the below example we are going to remove every second element from the number array.

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**Let’s see the complete example,**

import numpy as np # create sample numpy array numbers = np.array([34, 35, 78, 61, 56, 35, 90, 35]) print('Before removing elements:') print(numbers) # Nth value n = 2 # Create a mask where each Nth element # is marked as True mask = np.arange(len(numbers)) % n != 0 mask = ~mask # Remove every Nth element from the array numbers = numbers[mask] print('After removing elements:') print(numbers)

**Output**

Before removing elements: [34 35 78 61 56 35 90 35] After removing elements: [34 78 56 90]

## Summary

We learned how to delete every Nth element from a NumPy Array in Python.